欢迎来到起遇信息学
起遇信息学正处于上线筹建阶段,以下功能已全部开放免费体验: ✅ 完整题库浏览与代码提交评测(C / C++ / Python / Java 等) ✅ 入门到进阶的系列课程试读、作业与考试 ✅ AI 提示、AI 作业分析等智能助教功能 ✅ 赛事模拟与个人能力报告 ✅ 邮箱注册开放 ⏳ 付费课程订阅与微信/支付宝支付通道 ⏳ 手机号登录,微信扫码登录、微信公众号绑定 使用中如遇任何问题,欢迎通过页面底部 **"联系我们"** 与我们沟通。
CF1401A.Distance and Axis
Distance and Axis
We have a point with coordinate on -axis. We'd like to find an integer point (also on -axis), such that the absolute difference between the distance from to and the distance from to is equal to .
The description of the first test case.
Since sometimes it's impossible to find such point , we can, in one step, increase or decrease the coordinate of by . What is the minimum number of steps we should do to make such point exist?
Input
The first line contains one integer () — the number of test cases.
The only line of each test case contains two integers and () — the initial position of point and desirable absolute difference.
Output
For each test case, print the minimum number of steps to make point exist.
Note
In the first test case (picture above), if we set the coordinate of as then the absolute difference will be equal to and we don't have to move . So the answer is .
In the second test case, we can increase the coordinate of by and set the coordinate of as or . The absolute difference will be equal to , so the answer is .

Samples
6
4 0
5 8
0 1000000
0 0
1 0
1000000 1000000
0
3
1000000
0
1
0
在线编程 IDE
建议全屏模式获得最佳体验
| 进入全屏编程 | Alt+E |
| 递交评测 | Ctrl+Enter |
| 注释/取消注释 | Ctrl+/ |
| 缩放字体 | Ctrl+滚轮 |