CF1452C.Two Brackets

传统题 时间 2000 ms 内存 256 MiB 3 尝试 1 已通过 1 标签

Two Brackets

You are given a string ss, consisting of brackets of two types: '(', ')', '[' and ']'.

A string is called a regular bracket sequence (RBS) if it's of one of the following types:

  • empty string;
  • '(' + RBS + ')';
  • '[' + RBS + ']';
  • RBS + RBS.

where plus is a concatenation of two strings.

In one move you can choose a non-empty subsequence of the string ss (not necessarily consecutive) that is an RBS, remove it from the string and concatenate the remaining parts without changing the order.

What is the maximum number of moves you can perform?

Input

The first line contains a single integer tt (1t10001 \le t \le 1000) — the number of testcases.

Each of the next tt lines contains a non-empty string, consisting only of characters '(', ')', '[' and ']'. The total length of the strings over all testcases doesn't exceed 21052 \cdot 10^5.

Output

For each testcase print a single integer — the maximum number of moves you can perform on a given string ss.

Note

In the first example you can just erase the whole string.

In the second example you can first erase the brackets on positions 11 and 22: "[]()", then "()" is left. After that you can erase it whole. You could erase the whole string from the beginning but you would get one move instead of two.

In the third example you can first erase the brackets on positions 11 and 33: "([)]". They form an RBS "()". Then "[]" is left, so you can erase it whole.

In the fourth example there is no subsequence that is an RBS, so you can't perform a move at all.

In the fifth example you can erase the brackets on positions 22 and 44: ")[(]" and get ")(" as a result. You can erase nothing from it.

Samples

5
()
[]()
([)]
)]([
)[(]
1
2
2
0
1

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