CF1758B.XOR = Average

传统题 时间 2000 ms 内存 256 MiB 4 尝试 1 已通过 1 标签

XOR = Average

You are given an integer nn. Find a sequence of nn integers a1,a2,,ana_1, a_2, \dots, a_n such that 1ai1091 \leq a_i \leq 10^9 for all ii and $$a_1 \oplus a_2 \oplus \dots \oplus a_n = \frac{a_1 + a_2 + \dots + a_n}{n},$$where\oplus represents the bitwise XOR.

It can be proven that there exists a sequence of integers that satisfies all the conditions above.

Input

The first line of input contains tt (1t1041 \leq t \leq 10^4) — the number of test cases.

The first and only line of each test case contains one integer nn (1n1051 \leq n \leq 10^5) — the length of the sequence you have to find.

The sum of nn over all test cases does not exceed 10510^5.

Output

For each test case, output nn space-separated integers a1,a2,,ana_1, a_2, \dots, a_n satisfying the conditions in the statement.

If there are several possible answers, you can output any of them.

Note

In the first test case, 69=691=6969 = \frac{69}{1} = 69.

In the second test case, $13 \oplus 2 \oplus 8 \oplus 1 = \frac{13 + 2 + 8 + 1}{4} = 6$.

Samples

3
1
4
3
69
13 2 8 1
7 7 7

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