Let's denote the $f(x)$ function for a string $x$ as the number of distinct characters that the string contains. For example $f(\texttt{abc}) = 3$, $f(\texttt{bbbbb}) = 1$, and $f(\texttt{babacaba}) = 3$.

Given a string $s$, split it into two non-empty strings $a$ and $b$ such that $f(a) + f(b)$ is the maximum possible. In other words, find the maximum possible value of $f(a) + f(b)$ such that $a + b = s$ (the concatenation of string $a$ and string $b$ is equal to string $s$).

Input

The input consists of multiple test cases. The first line contains an integer $t$ ($1 \leq t \leq 10^4$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains an integer $n$ ($2 \leq n \leq 2\cdot10^5$) — the length of the string $s$.

The second line contains the string $s$, consisting of lowercase English letters.

It is guaranteed that the sum of $n$ over all test cases does not exceed $2\cdot10^5$.

Output

For each test case, output a single integer  — the maximum possible value of $f(a) + f(b)$ such that $a + b = s$.

Note

For the first test case, there is only one valid way to split aa into two non-empty strings a and a, and $f(\texttt{a}) + f(\texttt{a}) = 1 + 1 = 2$.

For the second test case, by splitting abcabcd into abc and abcd we can get the answer of $f(\texttt{abc}) + f(\texttt{abcd}) = 3 + 4 = 7$ which is maximum possible.

For the third test case, it doesn't matter how we split the string, the answer will always be $2$.

Samples

5
2
aa
7
abcabcd
5
aaaaa
10
paiumoment
4
aazz

2
7
2
10
3