CF1825B.LuoTianyi and the Table

传统题 时间 2000 ms 内存 256 MiB 5 尝试 1 已通过 1 标签

LuoTianyi and the Table

LuoTianyi gave an array bb of nmn \cdot m integers. She asks you to construct a table aa of size n×mn \times m, filled with these nmn \cdot m numbers, and each element of the array must be used exactly once. Also she asked you to maximize the following value:

$$\sum\limits_{i=1}^{n}\sum\limits_{j=1}^{m}\left(\max\limits_{1 \le x \le i, 1 \le y \le j}a_{x,y}-\min\limits_{1 \le x \le i, 1 \le y \le j}a_{x,y}\right)$$

This means that we consider nmn \cdot m subtables with the upper left corner in (1,1)(1,1) and the bottom right corner in (i,j)(i, j) (1in1 \le i \le n, 1jm1 \le j \le m), for each such subtable calculate the difference of the maximum and minimum elements in it, then sum up all these differences. You should maximize the resulting sum.

Help her find the maximal possible value, you don't need to reconstruct the table itself.

Input

Each test consists of multiple test cases. The first line contains a single integer tt (1t2001 \le t \le 200) — the number of test cases. The description of test cases follows.

The first line of each test case contains two integers nn and mm (2n,m1002 \le n, m \le 100) — the number of rows and columns of the table.

The second line of each test case contains nmn \cdot m integers b1,b2,,bnmb_1, b_2, \ldots, b_{n\cdot m} (105bi105-10^5 \le b_{i} \le 10^5) — the numbers you can put in the table.

Note, that integers in the array bb can be negative.

It is guaranteed that the sum of nmn \cdot m over all test cases doesn't exceed 21052\cdot 10^5.

Output

For each test case, output a single integer — the maximal value, that can be obtained.

Note

In the first test case, the table is follows:

4 1
1 3

In the subtable with the bottom right corner in (1,1)(1, 1), the difference of the maximal and minimal elements is 44=04 - 4 = 0.

In the subtable with the bottom right corner in (1,2)(1, 2), the difference of the maximal and minimal elements is 41=34 - 1 = 3.

In the subtable with the bottom right corner in (2,1)(2, 1), the difference of the maximal and minimal elements is 41=34 - 1 = 3.

In the subtable with the bottom right corner in (2,2)(2, 2), the difference of the maximal and minimal elements is 41=34 - 1 = 3.

Then the maximum possible value is 0+3+3+3=90+3+3+3=9.

In the second test case, all elements are equal, so all differences are 00, and the answer is 00.

Samples

5
2 2
1 3 1 4
2 2
-1 -1 -1 -1
2 3
7 8 9 -3 10 8
3 2
4 8 -3 0 -7 1
4 3
-32030 59554 16854 -85927 68060 -64460 -79547 90932 85063 82703 -12001 38762
9
0
64
71
1933711

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