欢迎来到起遇信息学
起遇信息学正处于上线筹建阶段,以下功能已全部开放免费体验: ✅ 完整题库浏览与代码提交评测(C / C++ / Python / Java 等) ✅ 入门到进阶的系列课程试读、作业与考试 ✅ AI 提示、AI 作业分析等智能助教功能 ✅ 赛事模拟与个人能力报告 ✅ 邮箱注册开放 ⏳ 付费课程订阅与微信/支付宝支付通道 ⏳ 手机号登录,微信扫码登录、微信公众号绑定 使用中如遇任何问题,欢迎通过页面底部 **"联系我们"** 与我们沟通。
CF2208A.Bingo Candies
Bingo Candies
Alice has a magic board. The board is described as a grid; each tile has a colored candy in it. The color of the candy in the -th row, -th column is .
Bob wants to know if he can rearrange the board in some way so that no row or column consists of candies of the same color.
Your task is to determine whether such a rearrangement exists.
Input
Each test contains multiple test cases. The first line contains the number of test cases (). The description of the test cases follows.
The first line of each test case contains an integer (), denoting the size of the board.
The following lines contain integers each; the -th integer on the -th line is (), denoting the color of candies on the board.
It is guaranteed that the sum of over all test cases does not exceed .
Output
For each test case, print "YES" if a valid rearrangement exists, and "NO" otherwise.
You can output the answer in any case (upper or lower). For example, the strings "yEs", "yes", "Yes", and "YES" will be recognized as positive responses.
Note
In the first test case, no row or column consists of all candies with the same color; the board can be left as it is.
In the second test case, the first row consists of all candies of color . The board can be rearranged by swapping with . After the rearrangement, the board becomes $$ \begin{matrix} 2 & 1 & 1 \ 1 & 3 & 4 \ 1 & 4 & 3 \end{matrix}$$Now no row or column consists of all candies with the same color.
In the third test case, no matter how the board is rearranged, there will always be at least one row or column consisting of all candies of color. Therefore, there is no valid rearrangement.
Samples
3
3
1 2 3
3 1 4
4 1 2
3
1 1 1
2 3 4
1 4 3
3
1 1 1
1 1 1
1 1 2
YES
YES
NO
在线编程 IDE
建议全屏模式获得最佳体验
| 进入全屏编程 | Alt+E |
| 递交评测 | Ctrl+Enter |
| 注释/取消注释 | Ctrl+/ |
| 缩放字体 | Ctrl+滚轮 |