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CF466C.Number of Ways
Number of Ways
CF466C · Number of Ways
- 难度:1700
- 标签:binary search、brute force、data structures、dp、two pointers
- 链接:https://codeforces.com/problemset/problem/466/C
- 时间限制:2 seconds 内存限制:256 megabytes
- 出现位置:Day22-阶段模拟4-S T1-T3综合卷
英文原题面
Statement
You've got array a[1], a[2], ..., a[n], consisting of n integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the same. More formally, you need to find the number of such pairs of indices i, j (2 ≤ i ≤ j ≤ n - 1), that .
Input
The first line contains integer n (1 ≤ n ≤ 5·105), showing how many numbers are in the array. The second line contains n integers a[1], a[2], ..., a[n] (|a[i]| ≤ 109) — the elements of array a.
Output
Print a single integer — the number of ways to split the array into three parts with the same sum.
样例
样例 1
输入:
5
1 2 3 0 3
输出:
2
样例 2
输入:
4
0 1 -1 0
输出:
1
样例 3
输入:
2
4 1
输出:
0
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