CF1359A.Berland Poker

传统题 时间 2000 ms 内存 256 MiB 5 尝试 1 已通过 1 标签

Berland Poker

The game of Berland poker is played with a deck of nn cards, mm of which are jokers. kk players play this game (nn is divisible by kk).

At the beginning of the game, each player takes nk\frac{n}{k} cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to xyx - y, where xx is the number of jokers in the winner's hand, and yy is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 00 points.

Here are some examples:

  • n=8n = 8, m=3m = 3, k=2k = 2. If one player gets 33 jokers and 11 plain card, and another player gets 00 jokers and 44 plain cards, then the first player is the winner and gets 30=33 - 0 = 3 points;
  • n=4n = 4, m=2m = 2, k=4k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 00 points;
  • n=9n = 9, m=6m = 6, k=3k = 3. If the first player gets 33 jokers, the second player gets 11 joker and 22 plain cards, and the third player gets 22 jokers and 11 plain card, then the first player is the winner, and he gets 32=13 - 2 = 1 point;
  • n=42n = 42, m=0m = 0, k=7k = 7. Since there are no jokers, everyone gets 00 jokers, everyone is a winner, and everyone gets 00 points.

Given nn, mm and kk, calculate the maximum number of points a player can get for winning the game.

Input

The first line of the input contains one integer tt (1t5001 \le t \le 500) — the number of test cases.

Then the test cases follow. Each test case contains three integers nn, mm and kk (2n502 \le n \le 50, 0mn0 \le m \le n, 2kn2 \le k \le n, kk is a divisors of nn).

Output

For each test case, print one integer — the maximum number of points a player can get for winning the game.

Note

Test cases of the example are described in the statement.

Samples

4
8 3 2
4 2 4
9 6 3
42 0 7
3
0
1
0

在线编程 IDE

建议全屏模式获得最佳体验