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CF1408A.Circle Coloring
Circle Coloring
You are given three sequences: ; ; .
For each , , , .
Find a sequence , that satisfy the following conditions:
- .
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements adjacent for and also elements and ) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer (): the number of test cases.
The first line of each test case contains one integer (): the number of elements in the given sequences.
The second line contains integers ().
The third line contains integers ().
The fourth line contains integers ().
It is guaranteed that , , for all .
Output
For each test case, print integers: (, ).
If there are several solutions, you can print any.
Note
In the first test case .
It is a correct answer, because:
- , ,
- , ,
All possible correct answers to this test case are: , , , , , .
In the second test case .
In this sequence , , , . Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case .
In this sequence , , , , , , . Also we can see, that no two adjacent elements of the sequence are equal.
Samples
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
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