欢迎来到起遇信息学
起遇信息学正处于上线筹建阶段,以下功能已全部开放免费体验: ✅ 完整题库浏览与代码提交评测(C / C++ / Python / Java 等) ✅ 入门到进阶的系列课程试读、作业与考试 ✅ AI 提示、AI 作业分析等智能助教功能 ✅ 赛事模拟与个人能力报告 ✅ 邮箱注册开放 ⏳ 付费课程订阅与微信/支付宝支付通道 ⏳ 手机号登录,微信扫码登录、微信公众号绑定 使用中如遇任何问题,欢迎通过页面底部 **"联系我们"** 与我们沟通。
CF1422A.Fence
Fence
Yura is tasked to build a closed fence in shape of an arbitrary non-degenerate simple quadrilateral. He's already got three straight fence segments with known lengths , , and . Now he needs to find out some possible integer length of the fourth straight fence segment so that he can build the fence using these four segments. In other words, the fence should have a quadrilateral shape with side lengths equal to , , , and . Help Yura, find any possible length of the fourth side.
A non-degenerate simple quadrilateral is such a quadrilateral that no three of its corners lie on the same line, and it does not cross itself.
Input
The first line contains a single integer — the number of test cases (). The next lines describe the test cases.
Each line contains three integers , , and — the lengths of the three fence segments ().
Output
For each test case print a single integer — the length of the fourth fence segment that is suitable for building the fence. If there are multiple answers, print any. We can show that an answer always exists.
Note
We can build a quadrilateral with sides , , , .
We can build a quadrilateral with sides , , , .
Samples
2
1 2 3
12 34 56
4
42
在线编程 IDE
建议全屏模式获得最佳体验
| 进入全屏编程 | Alt+E |
| 递交评测 | Ctrl+Enter |
| 注释/取消注释 | Ctrl+/ |
| 缩放字体 | Ctrl+滚轮 |