CF1525A.Potion-making

传统题 时间 2000 ms 内存 256 MiB 3 尝试 1 已通过 1 标签

Potion-making

You have an initially empty cauldron, and you want to brew a potion in it. The potion consists of two ingredients: magic essence and water. The potion you want to brew should contain exactly k %k\ \% magic essence and (100k) %(100 - k)\ \% water.

In one step, you can pour either one liter of magic essence or one liter of water into the cauldron. What is the minimum number of steps to brew a potion? You don't care about the total volume of the potion, only about the ratio between magic essence and water in it.

A small reminder: if you pour ee liters of essence and ww liters of water (e+w>0e + w \gt 0) into the cauldron, then it contains ee+w100 %\frac{e}{e + w} \cdot 100\ \% (without rounding) magic essence and we+w100 %\frac{w}{e + w} \cdot 100\ \% water.

Input

The first line contains the single tt (1t1001 \le t \le 100) — the number of test cases.

The first and only line of each test case contains a single integer kk (1k1001 \le k \le 100) — the percentage of essence in a good potion.

Output

For each test case, print the minimum number of steps to brew a good potion. It can be proved that it's always possible to achieve it in a finite number of steps.

Note

In the first test case, you should pour 33 liters of magic essence and 9797 liters of water into the cauldron to get a potion with 3 %3\ \% of magic essence.

In the second test case, you can pour only 11 liter of essence to get a potion with 100 %100\ \% of magic essence.

In the third test case, you can pour 11 liter of magic essence and 33 liters of water.

Samples

3
3
100
25
100
1
4

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