CF1834B.Maximum Strength

传统题 时间 2000 ms 内存 256 MiB 5 尝试 1 已通过 1 标签

Maximum Strength

Fedya is playing a new game called "The Legend of Link", in which one of the character's abilities is to combine two materials into one weapon. Each material has its own strength, which can be represented by a positive integer xx. The strength of the resulting weapon is determined as the sum of the absolute differences of the digits in the decimal representation of the integers at each position.

Formally, let the first material have strength X=x1x2xnX = \overline{x_{1}x_{2} \ldots x_{n}}, and the second material have strength Y=y1y2ynY = \overline{y_{1}y_{2} \ldots y_{n}}. Then the strength of the weapon is calculated as $|x_{1} - y_{1}| + |x_{2} - y_{2}| + \ldots + |x_{n} - y_{n}|$. If the integers have different lengths, then the shorter integer is padded with leading zeros.

Fedya has an unlimited supply of materials with all possible strengths from LL to RR, inclusive. Help him find the maximum possible strength of the weapon he can obtain.

An integer C=c1c2ckC = \overline{c_{1}c_{2} \ldots c_{k}} is defined as an integer obtained by sequentially writing the digits c1,c2,,ckc_1, c_2, \ldots, c_k from left to right, i.e. $10^{k-1} \cdot c_1 + 10^{k-2} \cdot c_2 + \ldots + c_k$.

Input

Each test contains multiple test cases. The first line contains the number of test cases tt (1t5001 \le t \le 500). The description of the test cases follows.

The first line of each test case contains two integers LL and RR (1LR<101001 \le L \le R \lt 10^{100}) — the decimal representation of the integers representing the minimum and maximum strength of the materials that Fedya has. It is guaranteed that the integers LL and RR do not contain leading zeros.

Note that the input data may not fit into standard 3232-bit or 6464-bit integer data types.

Output

For each test case print one integer — the maximum possible strength of the weapon that Fedya can obtain from the given materials.

Note

In the first test case, the weapon made from materials with strengths 5353 and 5757 will have the maximum possible strength: 55+37=4|5 - 5| + |3 - 7| = 4.

In the second test case, the maximum strength is achieved with materials with strengths 190190 and 209209: 12+90+09=19|1 - 2| + |9 - 0| + |0 - 9| = 19.

In the fourth test case, there is only one valid strength, so the answer is 00.

In the sixth test case, the maximum strength is achieved with materials with strengths 19091909 and 9090: 10+90+09+90=28|1 - 0| + |9 - 0| + |0 - 9| + |9 - 0| = 28. Note that the shorter integer was padded with leading zeros.

Samples

6
53 57
179 239
13 37
132228 132228
54943329752812629795 55157581939688863366
88 1914
4
19
11
0
163
28

在线编程 IDE

建议全屏模式获得最佳体验