欢迎来到起遇信息学
起遇信息学正处于上线筹建阶段,以下功能已全部开放免费体验: ✅ 完整题库浏览与代码提交评测(C / C++ / Python / Java 等) ✅ 入门到进阶的系列课程试读、作业与考试 ✅ AI 提示、AI 作业分析等智能助教功能 ✅ 赛事模拟与个人能力报告 ✅ 邮箱注册开放 ⏳ 付费课程订阅与微信/支付宝支付通道 ⏳ 手机号登录,微信扫码登录、微信公众号绑定 使用中如遇任何问题,欢迎通过页面底部 **"联系我们"** 与我们沟通。
CF1969B.Shifts and Sorting
Shifts and Sorting
Let's define a cyclic shift of some string as a transformation from into . In other words, you take one last character and place it before the first character while moving all other characters to the right.
You are given a binary string (a string consisting of only 0-s and/or 1-s).
In one operation, you can choose any substring () and cyclically shift it. The cost of such operation is equal to (or the length of the chosen substring).
You can perform the given operation any number of times. What is the minimum total cost to make sorted in non-descending order?
Input
The first line contains a single integer () — the number of test cases.
The first and only line of each test case contains a binary string (; {0, 1}) — the string you need to sort.
Additional constraint on the input: the sum of lengths of strings over all test cases doesn't exceed .
Output
For each test case, print the single integer — the minimum total cost to make string sorted using operation above any number of times.
Note
In the first test case, you can choose the whole string and perform a cyclic shift: 10 01. The length of the substring is , so the cost is .
In the second test case, the string is already sorted, so you don't need to perform any operations.
In the third test case, one of the optimal strategies is the next:
- choose substring :
1100001100; - choose substring :
0110000110; - choose substring :
0011000011.
The total cost is .
Samples
5
10
0000
11000
101011
01101001
2
0
9
5
11
在线编程 IDE
建议全屏模式获得最佳体验
| 进入全屏编程 | Alt+E |
| 递交评测 | Ctrl+Enter |
| 注释/取消注释 | Ctrl+/ |
| 缩放字体 | Ctrl+滚轮 |